Dec 3, 2024
For m=1, m^32<2^m.
For m=2, m^32>2^m.
Therefore, there must be a solution between 1 and 2 (barring discontinuities).
That said, the puzzle asked for a natural number and John's cool number is not.
For m=1, m^32<2^m.
For m=2, m^32>2^m.
Therefore, there must be a solution between 1 and 2 (barring discontinuities).
That said, the puzzle asked for a natural number and John's cool number is not.