Indeed, it works for any quantity of the form (n^(1/n))^n=n, see my comment,

I tried with the calculator and first you seemed to be correct, but then I realized I was placing…
1
brian vant-hull
Aaron Tovish
Mar 11, 2024
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Indeed, it works for any quantity of the form (n^(1/n))^n=n, see my comment,
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Written by Aaron Tovish47 followers
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