r^2=(4-r)^2+9; 0=-8r+16+9; r=25/8; Circ=25PI/4

Can You Find the Circumference of This Circle??
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Nnamdi Samuel
Aaron Tovish
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Nov 6, 2024
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r^2=(4-r)^2+9; 0=-8r+16+9; r=25/8; Circ=25PI/4
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Written by Aaron Tovish46 Followers
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