Aaron Tovish
Apr 19, 2024

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There sum is infinite!

We have tan(nth theta)=1/n. As n gets larger tan(theta) approached theta. So, this reduces to the sum angle to the sum of the recipricals -- which has no limit.

In would be interesting to know what n must equal for the sum to reach 2pi, 4pi, etc. They must be a huge numbers.

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